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Through my research on the bead road theory over the past few months, I have discovered an interesting phenomenon: for every large road, when arranged in a 2-bead road format, there are 2 different road patterns; when arranged in a 3-bead road format, there are 3 different road patterns; when arranged in a 4-bead road format, there are 4 different road patterns, and so on for N-bead road arrangements. How is this explained? Let me provide an example, assuming B=1, P=2, and temporarily ignoring T.
Suppose the large road follows this pattern: 12121212121212121212121212121212.
When arranged in a 2-bead road format, it becomes BPBPBPBPBP.
If we remove the first bead, we get the exact opposite result:
21212121212121212121212121212121.
It turns into PBPBPBPBPB.
If we remove one more bead, we return to the first scenario.
So, for every large road, when arranged in a 2-bead road format, there are 2 different road patterns.
Let's take another example:
Large road: 122122122122122122.
When arranged in a 3-bead road format:
122, 122, 122, 122, 122, 122.
If we remove the first bead, it becomes:
221, 221, 221, 221.
If we remove the first 2 beads, it becomes:
212, 212, 212, 212.
If we remove 3 beads, it returns to 122, 122, 122.
Therefore, for every large road, when arranged in a 3-bead road format, there are 3 different road patterns.
Similarly, when arranged in an N-bead road format, there are N different road patterns.
The significance of this is:
1. For the sequence 81, the arrangement of 2-bead and 3-bead roads starting from the first bead, as opposed to starting from the 2nd and 3rd beads, results in different outcomes.
2. It provides the basis for the versatility of bets in the Three Roads theory.
3. For a particular shoe, the bead road starting from the first bead may be a losing road, while the one starting from the 2nd or 3rd bead may be a winning road. |
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Post time 17-9-2023 17:27:04